DISQUS

steveharris · 2 years ago

Proposed 1-liner:

Hash#invert returns a new hash where the keys of the new hash are the values of the old hash, and vice-versa. If the original hash contains multiple keys that map to the same value, the new hash will contain a single entry for that value (now the new key) and which of the original keys becomes the new value is not predictable.

Write a one-liner which inverts a hash, but where each value in the new hash is an array containing all the keys of the original hash.

Now, write a one-liner like the above, but if there is only one (new) value, it should be a simple value, not an array.

- Steve

Philipp · 2 years ago

This is a little tricky, since punctuation gets in the way (you can't use a plain "split" because those "Indians" at the end have a trailing ".")
I think this covers most situations, but "\b" may be a little obscure.

s.split(/\b/).map {|w| d.include?(w) ? w[0].chr + "*" * (w.length - 1) : w}.join

Philipp · 2 years ago

Plus, you can't censor things containing a mix of word and non-word characters. If you put "can't" in your banned word list, it won't be filtered out.
I'll leave the substring-based solution to someone else.
Also, what I posted censors case-sensitively. That probably ought to be corrected, too. Making it:
d.map {|b| b.upcase}.include?(w.upcase)
should take case of that.
Oneliners that try to cover all the bases seem to get quite ornate.

jgn · 2 years ago

Nice!

Mhoram · 2 years ago

d.inject(a) { |censored, bad_word| censored.gsub( Regexp.new( bad_word ), '*' * bad_word.length) }

jgn · 2 years ago

Can you add some code to show it working . . . ?

jgn · 2 years ago

Good one.